If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+3x-9=x-1+3
We move all terms to the left:
x^2+3x-9-(x-1+3)=0
We add all the numbers together, and all the variables
x^2+3x-(x+2)-9=0
We get rid of parentheses
x^2+3x-x-2-9=0
We add all the numbers together, and all the variables
x^2+2x-11=0
a = 1; b = 2; c = -11;
Δ = b2-4ac
Δ = 22-4·1·(-11)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{3}}{2*1}=\frac{-2-4\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{3}}{2*1}=\frac{-2+4\sqrt{3}}{2} $
| 4x+2(x+4)=24 | | 5s+1=16 | | –2j=–42 | | a−-9=-11 | | -8v-24=-4(v-3) | | 3=(10x+9) | | 3x^2+48=-24x | | 41 (x−12)=−5 | | u/9=-3 | | -1h+2=2h+-1 | | u/9=–3 | | ^-13-16z-^-18=^-10 | | 4x=6=52 | | (3x-5)+(x-1)=180 | | 1/2s=7/9 | | 12=-0.5x | | 25=9-3.2k | | x^2+3x-9=|x-1|+3 | | 4x+6=8x−102 | | 3(q-5)+3=9 | | 18=w+11 | | 4b^2-3=-31 | | 12(x-2)=4(x+2) | | h+990=-1 | | 1/14(x-64)=1+x | | -1x+2=2x+-1 | | 14x+17+10x+9=180 | | y=2–5 | | a+1/2=6/7 | | 7x+11x+9=153 | | 2+4x3-8=81 | | 11p+6=9p-2 |